Question

Match the following List-I with corresponding List-II.

\[ \begin{array}{|c|l|c|l|} \hline \text{List-I} & & \text{List-II} & \\ \hline (a) & \text{Binomial} & (i) & x=0,1 \text{ only two values} \\ \hline (b) & \text{Normal} & (ii) & \text{Discrete distribution} \\ \hline (c) & \text{Statistic} & (iii) & \text{Symmetric distribution} \\ \hline (d) & \text{Bernoulli} & (iv) & \text{Not a distribution} \\ \hline \end{array} \]

• A. a-i, b-ii, c-iii, d-iv
• B. a-iv, b-iii, c-ii, d-i
• C. a-ii, b-iii, c-iv, d-i
• D. a-ii, b-iv, c-iii, d-i

Hint:

Remember: \[ \text{Bernoulli} \rightarrow \{0,1\} \] \[ \text{Binomial} \rightarrow \text{Discrete Distribution} \] \[ \text{Normal} \rightarrow \text{Symmetric Distribution} \] \[ \text{Statistic} \rightarrow \text{Not a Distribution} \]

Answer 1

The Correct Option is C

Step 1: Match Binomial Distribution.
A Binomial Distribution counts the number of successes in a fixed number of trials. It is a discrete probability distribution. \[ (a)\rightarrow(ii) \]

Step 2: Match Normal Distribution.
A Normal Distribution is bell-shaped and symmetric about its mean. \[ (b)\rightarrow(iii) \]

Step 3: Match Statistic.
A statistic is a numerical measure computed from sample data. It is not itself a probability distribution. \[ (c)\rightarrow(iv) \]

Step 4: Match Bernoulli Distribution.
A Bernoulli random variable takes only two values: \[ 0 \quad \text{or} \quad 1 \] representing failure and success respectively. \[ (d)\rightarrow(i) \]

Step 5: Write the final matching.
\[ a-ii,\quad b-iii,\quad c-iv,\quad d-i \] Therefore, \[ {a-ii,\; b-iii,\; c-iv,\; d-i} \] Hence option (C) is correct.