Question:medium

Match the following:

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Classify hydrides based on electron count around central atom: electron precise (octet satisfied), electron deficient (less than octet), electron rich (lone pairs), and saline (ionic character).
Updated On: Jun 26, 2026
  • A – (ii), B – (iii), C – (i), D – (iv)
  • A – (i), B – (iii), C – (iv), D – (ii)
  • A – (iv), B – (ii), C – (iii), D – (i)
  • A – (ii), B – (i), C – (iv), D – (iii)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Recall hydride types by electron count around the central atom.
Electron-precise (octet exactly): SiH\(_4\). Ionic hydride (electropositive metal): MgH\(_2\). Electron-deficient (3c-2e bonds): B\(_2\)H\(_6\). Electron-rich (lone pairs on central atom): H\(_2\)O.

Step 2: Match to options (i = electron-precise, ii = electron-rich, iii = ionic, iv = electron-deficient).
A(SiH\(_4\))-i, B(MgH\(_2\))-iii, C(B\(_2\)H\(_6\))-iv, D(H\(_2\)O)-ii.
\[ \boxed{A\text{-}i,\ B\text{-}iii,\ C\text{-}iv,\ D\text{-}ii} \]
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