Question

Match Structure with their Common Name:

Choose the correct answer from the options given below:

• A. (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
• B. (A)-(I), (B)-(II), (C)-(IV), (D)-(III)
• C. (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
• D. (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

Hint:

Vinyl chloride = \(CH_2=CHCl\), Allyl chloride = \(CH_2=CHCH_2Cl\), Ethylene dichloride = \(ClCH_2CH_2Cl\), Ethylidene chloride = \(CH_3CHCl_2\).

Answer 1

The Correct Option is A

Step 1: Identify compound (A).
\[ H_2C=CHCH_2Cl \] contains an allyl group attached to chlorine. Therefore, \[ (A)\rightarrow(I) \] \[ {\text{Allyl chloride}} \]

Step 2: Identify compound (B).
\[ CH_3CHCl_2 \] contains two chlorine atoms attached to the same carbon atom. This is called ethylidene chloride. \[ (B)\rightarrow(IV) \]

Step 3: Identify compound (C).
\[ ClCH_2CH_2Cl \] is 1,2-dichloroethane. Its common name is ethylene dichloride. \[ (C)\rightarrow(II) \]

Step 4: Identify compound (D).
\[ H_2C=CHCl \] is chloroethene. Its common name is vinyl chloride. \[ (D)\rightarrow(III) \]

Step 5: Write final matching.
\[ (A)-(I),\ (B)-(IV),\ (C)-(II),\ (D)-(III) \] Hence, \[ {\text{Option (A)}} \]