Question

Match List I with List II:

List I	List II
A. $E = h\nu$  B. Diffraction and Interference  C. $\lambda = \frac{h}{p}$  D. Compton effect	I. de Broglie wavelength  II. Particle nature of light  III. Wave nature of light  IV. Energy of photon

• A. A-IV, B-I, C-II, D-III
• B. A-I, B-IV, C-III, D-II
• C. A-IV, B-III, C-II, D-I
• D. A-IV, B-III, C-I, D-II

Hint:

To remember the "nature" of light: Wave nature is proved by Interference/Diffraction/Polarization. Particle nature is proved by Photoelectric effect/Compton effect.

Answer 1

The Correct Option is D

Let's match each item in List I with its corresponding concept in List II based on the principles of physics:

1. A. \(E = h\nu\)
   • This equation represents the energy of a photon, where \( E \) is the energy, \( h \) is Planck's constant, and \( \nu \) is the frequency of the light.
   • Therefore, this matches with IV. Energy of photon.
2. B. Diffraction and Interference
   • Both diffraction and interference are phenomena that explain the wave nature of light. They occur when light waves overlap and the resultant pattern is due to wave superposition.
   • Therefore, this matches with III. Wave nature of light.
3. C. \(λ = \frac{h}{p}\)
   • This expression is known as the de Broglie wavelength formula, where \( \lambda \) is the wavelength, \( h \) is Planck's constant, and \( p \) is the momentum of the particle.
   • Therefore, this matches with I. de Broglie wavelength.
4. D. Compton effect
   • The Compton effect demonstrates the particle nature of light. It involves the scattering of photons by electrons, resulting in a change in wavelength that confirms the particle-like properties of light.
   • Therefore, this matches with II. Particle nature of light.

Based on the correct matches, the answer is: A-IV, B-III, C-I, D-II.