Question

Match List-I with List-II:

List-I	List-II
(A) Lyman	(i) n = 2, 3, 4, ...
(B) Balmer	(ii) n = 3, 4, 5, ...
(C) Paschen	(iii) n = 4, 5, 6, ...
(D) Bracket	(iv) n = 5, 6, 7, ...

Choose the correct answer from the options given below:

• (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
• (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
• (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
• (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Hint:

Lyman transitions end in n=1, emitting UV radiation; Balmer transitions end in n=2 and emit visible light; Paschen ends in n=3 with IR radiation, and Bracket series is in far IR with n=4.

Answer 1

The Correct Option is A

Hydrogen spectral series and their transitions:
• Lyman series: transitions to n=1 from higher energy levels (n=2, 3, 4, ...).
• Balmer series: transitions to n=2 from higher energy levels (n=3, 4, 5, ...).
• Paschen series: transitions to n=3 from higher energy levels (n=4, 5, 6, ...).
• Bracket series: transitions to n=4 from higher energy levels (n=5, 6, 7, ...).
The correct matching is: (A) - (i), (B) - (ii), (C) - (iii), (D) - (iv).