A different way to solve this is by eliminating the wrong pairs one at a time.
First, a depression is opposite to a hill: on a hill the centre has the highest value, but in a depression the centre has the lowest value, so the values read higher as you move outward. This fixes (C) with (II).
Second, contour lines always meet a ridge or valley line at 90 degrees, never obliquely, so (D) must pair with (III), at right angles.
Third, on hilly ground the slope is steepest near the summit, so contours bunch up there, giving (A) close contour lines with (IV) top of hill.
Fourth, by elimination the remaining pair (B) wider contour lines goes with (I) foot hill, where the ground is flatter.
\[ oxed{(A)-(IV),\ (B)-(I),\ (C)-(II),\ (D)-(III)} \]