Question:easy

Match List-I with List-II:
List-I (Process)List-II (Characteristic)
(A) Adiabatic(I) No volume change takes place
(B) Isochoric(II) No pressure change takes place
(C) Isobaric(III) No temperature change takes place
(D) Isothermal(IV) No heat transfer takes place

Choose the correct answer from the options given below:

Show Hint

The iso prefix tells you which quantity stays constant in each of the four processes.
  • (A) - (III), (B) - (IV), (C) - (II), (D) - (I)
  • (A) - (II), (B) - (I), (C) - (IV), (D) - (III)
  • (A) - (I), (B) - (III), (C) - (IV), (D) - (II)
  • (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Use the process names themselves as clues, since each part of the name hints at what stays fixed. Iso means same or equal, so isochoric keeps volume equal, isobaric keeps pressure equal, and isothermal keeps temperature equal.
Step 2: That direct reading gives isochoric with no volume change (I), isobaric with no pressure change (II), and isothermal with no temperature change (III), without needing any calculation.
Step 3: Adiabatic does not fit the iso pattern, its name refers to heat being unable to pass into or out of the system. That is precisely no heat transfer takes place, which is (IV).
Step 4: Matching all four gives (A) Adiabatic to (IV), (B) Isochoric to (I), (C) Isobaric to (II), (D) Isothermal to (III).
\[\boxed{\text{(A)-(IV), (B)-(I), (C)-(II), (D)-(III)}}\]
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