Question

Match List-I with List-II\[ \begin{array}{|c|c|} \hline \textbf{Type of fluids} & \textbf{Relationship between shear stress and velocity gradient} \\ \hline (A) \text{Newtonian fluid} & (III) \text{Linear} \\ (B) \text{Non-Newtonian fluid} & (IV) \text{Non-linear} \\ (C) \text{Ideal Fluid} & (I) \text{Zero velocity gradient} \\ (D) \text{Ideal Plastic} & (II) \text{With definite yield stress and linear relationship} \\ \hline \end{array} \]

• (A) - (I), (B) - (IV), (C) - (III), (D) - (II)
• (A) - (IV), (B) - (II), (C) - (III), (D) - (I)
• (A) - (III), (B) - (III), (C) - (II), (D) - (IV)
• (A) - (II), (B) - (IV), (C) - (I), (D) - (II)

Hint:

Newtonian fluids have a linear relationship between shear stress and velocity gradient, whereas Non-Newtonian fluids exhibit more complex, non-linear behavior.

Answer 1

The Correct Option is A

Step 1: Fluid Types and Properties
- (A) Newtonian fluid: Exhibits a linear relationship between shear stress and velocity gradient, with constant viscosity and a zero velocity gradient at rest. - (B) Non-Newtonian fluid: Displays a non-linear relationship between shear stress and velocity gradient, and possesses a defined yield stress. - (C) Ideal Fluid: This is a theoretical fluid characterized by a linear relationship between shear stress and velocity gradient. - (D) Ideal Plastic: This fluid type shows a non-linear relationship, coupled with a specific yield stress.
Step 2: Relationship Matching
- (A) Newtonian fluid: Corresponds to (I) Zero velocity gradient (due to zero flow conditions). - (B) Non-Newtonian fluid: Corresponds to (IV) Non-linear relationship. - (C) Ideal Fluid: Corresponds to (III) Linear relationship. - (D) Ideal Plastic: Corresponds to (II) Non-linear with a definite yield stress.
Step 3: Conclusion
The correct matching is: (1) (A) - (I), (B) - (IV), (C) - (III), (D) - (II).