Question

Match items of Column-I with those in Column-II. \[ \begin{array}{llll} (a) & \text{A laevorotatory carbohydrate} & (p) & \text{Sucrose} \\[6pt] (b) & \text{A non-reducing sugar} & (q) & \text{Maltose} \\[6pt] (c) & \text{Carbohydrate stored in animal body} & (r) & \text{Fructose} \\[6pt] (d) & \text{A disaccharide made of two glucose units} & (s) & \text{Glycogen} \end{array} \]

• A. \((a)-(s),\ (b)-(r),\ (c)-(q),\ (d)-(p)\)
• B. \((a)-(r),\ (b)-(s),\ (c)-(p),\ (d)-(q)\)
• C. \((a)-(r),\ (b)-(p),\ (c)-(s),\ (d)-(q)\)
• D. \((a)-(q),\ (b)-(r),\ (c)-(p),\ (d)-(s)\)

Hint:

\[ \begin{aligned} \text{Fructose} &: \text{Laevorotatory sugar} \\ \text{Sucrose} &: \text{Non-reducing sugar} \\ \text{Maltose} &: \text{Two glucose units} \\ \text{Glycogen} &: \text{Animal storage carbohydrate} \end{aligned} \]

Answer 1

The Correct Option is C

Step 1: Plan the matching.
We match each description to the sugar that fits it.

Step 2: A laevorotatory carbohydrate (a).
Fructose rotates plane-polarised light to the left (laevo). So $(a)$ goes with $(r)$, fructose.

Step 3: A non-reducing sugar (b).
Sucrose has no free aldehyde or ketone group, so it does not reduce Tollens or Fehling. So $(b)$ goes with $(p)$, sucrose.

Step 4: Carbohydrate stored in animal body (c).
Animals store carbohydrate as glycogen. So $(c)$ goes with $(s)$, glycogen.

Step 5: A disaccharide of two glucose units (d).
Maltose is made of two glucose units joined together. So $(d)$ goes with $(q)$, maltose.

Step 6: Collect the pairs.
Putting it together: $(a)-(r),\ (b)-(p),\ (c)-(s),\ (d)-(q)$, which is the third option.
\[ \boxed{(a)-(r),\ (b)-(p),\ (c)-(s),\ (d)-(q)} \]