Question:medium

Lorentz magnetic force is acting on a particle of charge q moving with velocity $\vec{V}$ in a magnetic field $\vec{B}$. The work done by this force on the charged particle is}

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Magnetic force only changes the direction of velocity, not its magnitude (kinetic energy).
Updated On: Jun 19, 2026
  • zero
  • one
  • infinity
  • $qB \sin \theta$
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Question:
The question asks for the work done by a magnetic force on a moving charge.

Step 2: Key Formula or Approach:

1. Magnetic force \( \vec{F}_m = q(\vec{V} \times \vec{B}) \).
2. Work done \( W = \int \vec{F} \cdot d\vec{s} \).

Step 3: Detailed Explanation:

The magnetic force \( \vec{F}_m \) is the result of a cross product between \( \vec{V} \) and \( \vec{B} \).
By definition of the cross product, \( \vec{F}_m \) is always perpendicular to both \( \vec{V} \) and \( \vec{B} \).
Since \( \vec{F}_m \perp \vec{V} \), the dot product \( \vec{F}_m \cdot \vec{V} = 0 \).
The displacement \( d\vec{s} \) is in the direction of velocity \( \vec{V} \).
Thus, \( \vec{F}_m \cdot d\vec{s} = F_m \cdot ds \cos(90^\circ) = 0 \).
Therefore, the work done is zero.

Step 4: Final Answer:

The work done by the Lorentz magnetic force is zero.
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