Question:medium
\( \lim_{x \to 0} \frac{\log(1 + 3x^2){x(e^{5x} - 1)} = \)}
\( \lim_{x \to 0} \frac{\log(1 + 3x^2){x(e^{5x} - 1)} = \)}
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For limits involving \( \log(1+kx^n) \) and \( (e^{mx}-1) \), you can replace the terms with their first-order approximations \( kx^n \) and \( mx \) respectively for quick evaluation.
\( \frac{3x^2}{x(5x)} = \frac{3}{5} \).
Updated On: May 6, 2026
- \( \frac{3}{5} \)
- \( \frac{5}{3} \)
- \( \frac{-3}{5} \)
- \( \frac{-5}{3} \)
- \( 1 \)
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The Correct Option is A
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