Question:medium

Let \(z = \frac{a - \frac{i}{2}}{i - 2}\), where \(a\) is a real number and \(i = \sqrt{-1}\). If \(\text{Im}(z) = 0\), then the value of \(a\) is equal to

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If \(\frac{z_1}{z_2}\) is purely real, then \(z_1 \overline{z_2}\) is also purely real. You only need to set the imaginary part of the product of the numerator and the conjugate of the denominator to zero.
Updated On: Jun 24, 2026
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The Correct Option is A

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