Question:medium

Let $X_{i} \sim N(0,1), i=1,2, \dots$ be independent random variables. If $T_{n}=\sum_{i=1}^{n} X_{i}^{2}$, then $\lim_{n \rightarrow \infty} P(T_{n} > n+2 \sqrt{2 n})$ is equal to

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For large $n$, $\chi^2_n$ is essentially normal. The term $n + k\sqrt{2n}$ represents the mean plus $k$ standard deviations. The probability of being above that is $1-\Phi(k)$.
Updated On: Jun 6, 2026
  • $\Phi(2)$
  • $\Phi(-2)$
  • $1/2$
  • $1-\Phi(-2)$
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The Correct Option is B

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