Question:medium

Let \( w \neq \pm 1 \) be a complex number. If \( |w| = 1 \) and \( z = \frac{w - 1}{w + 1} \), then \( \text{Re}(z) \) is equal to:

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Geometrically, if $|w|=1$, then $z = \frac{w-1}{w+1}$ maps a point on the unit circle to the imaginary axis. This is a common transformation in complex analysis.
Updated On: May 6, 2026
  • \( 1 \)
  • \( \frac{1}{|w + 1|} \)
  • \( \text{Re}(w) \)
  • \( 0 \)
  • \( w + \bar{w} \)
Show Solution

The Correct Option is D

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