Question:medium

Let $\vec{F}(x, y, z) = x \hat{i} + x y \hat{j} + \hat{k}$, then $\text{curl}(\vec{F})$ is

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Notice that $F_x$ and $F_y$ do not depend on $z$, and $F_z$ is constant. Thus all $z$-derivatives are zero, leaving only the $x,y$ derivative in the $\hat{k}$ component!
Updated On: Jul 29, 2026
  • $\hat{j} + x \hat{k}$
  • $y \hat{k}$
  • $\hat{i} + x \hat{j}$
  • $x \hat{i} + x y \hat{j} + \hat{k}$
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The Correct Option is B

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