Question:medium

Let $\sum_{n=1}^\infty \frac{1}{n^2}$ and $\sum_{n=1}^\infty \frac{1}{n^{\frac{1}{2}}}$ be series, then}

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Remember the threshold value for the p-series test:
- Any power \(\mathbf{p}\) strictly greater than 1 converges.
- Even a value like \(p = 1.0001\) converges.
- Any power \(\mathbf{p}\) less than or equal to 1 (including the harmonic series where \(p=1\)) diverges.
  • both are convergent
  • both are divergent
  • $\sum_{n=1}^\infty \frac{1}{n^2}$ is convergent and $\sum_{n=1}^\infty \frac{1}{n^{\frac{1}{2}}}$ is divergent
  • $\sum_{n=1}^\infty \frac{1}{n^2}$ is divergent and $\sum_{n=1}^\infty \frac{1}{n^{\frac{1}{2}}}$ is convergent
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The Correct Option is C

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