Question:medium
Let $P = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 10 & 100 & -1 \end{pmatrix}$. Then $P^{4052}$ is equal to:
Let $P = \begin{pmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 10 & 100 & -1 \end{pmatrix}$. Then $P^{4052}$ is equal to:
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If $A^2 = I$, then even powers give identity and odd powers give $A$.
Updated On: Apr 24, 2026
- $P$
- $P^T$
- $I$, the unit matrix of order 3
- $-P^T$
- $2P^T$
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The Correct Option is C
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