Question

Let P be the parabola, whose focus is $ (-2, 1) $ and directrix is $ 2x + y + 2 = 0 $. Then the sum of the ordinates of the points on P, whose abscissa is -2, is:

• A. \( \frac{3}{2} \)
• B. \( \frac{5}{2} \)
• C. \( \frac{1}{4} \)
• D. \( \frac{3}{4} \)

Hint:

For problems involving parabolas, remember that the distance from a point on the parabola to the focus is equal to its distance from the directrix. Use this property to set up equations and solve for the coordinates.

Answer 1

The Correct Option is A

A parabola is defined as the set of all points equidistant from a fixed point (the focus) and a fixed line (the directrix). Given: Focus \( F = (-2, 1) \) and Directrix: \( 2x + y + 2 = 0 \). The distance from a point \( P(x_1, y_1) \) on the parabola to the focus is \( \sqrt{(x_1 + 2)^2 + (y_1 - 1)^2} \). The perpendicular distance from \( P(x_1, y_1) \) to the directrix \( 2x + y + 2 = 0 \) is \( \frac{|2x_1 + y_1 + 2|}{\sqrt{2^2 + 1^2}} = \frac{|2x_1 + y_1 + 2|}{\sqrt{5}} \). For \( x_1 = -2 \), equating these distances yields \( \sqrt{(-2 + 2)^2 + (y_1 - 1)^2} = \frac{|2(-2) + y_1 + 2|}{\sqrt{5}} \). Solving this equation for \( y_1 \) gives \( y_1 = \frac{3}{2} \). Therefore, the sum of the ordinates of the points on the parabola is \( \frac{3}{2} \).