Question:medium
Let $O$ be the origin. Let $\overrightarrow{OA} = \vec{a}$ and $\overrightarrow{OB} = \vec{b}$ be the position vectors of the points $A$ and $B$ respectively. A point $P$ divides the line segment $AB$ internally in the ratio $m:n$. Then $\overrightarrow{AP}$ is equal to:
Let $O$ be the origin. Let $\overrightarrow{OA} = \vec{a}$ and $\overrightarrow{OB} = \vec{b}$ be the position vectors of the points $A$ and $B$ respectively. A point $P$ divides the line segment $AB$ internally in the ratio $m:n$. Then $\overrightarrow{AP}$ is equal to:
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Always use $\vec{AP} = \vec{OP} - \vec{OA}$ after finding section formula.
Updated On: Apr 24, 2026
- $\frac{2n(\vec{b}-\vec{a})}{m+n}$
- $\frac{n(\vec{b}+\vec{a})}{m+n}$
- $\frac{n(\vec{b}-\vec{a})}{m-n}$
- $\frac{m(\vec{b}-\vec{a})}{m+n}$
- $\frac{n(\vec{b}-\vec{a})}{m+n}$
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The Correct Option is D
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