Question:medium
Let \( f(x) = (x^5 - 1)(x^3 + 1) \), \( g(x) = (x^2 - 1)(x^2 - x + 1) \) and let \( h(x) \) be such that \( f(x) = g(x)h(x) \). Then \( \lim_{x \to 1} h(x) \) is:
Let \( f(x) = (x^5 - 1)(x^3 + 1) \), \( g(x) = (x^2 - 1)(x^2 - x + 1) \) and let \( h(x) \) be such that \( f(x) = g(x)h(x) \). Then \( \lim_{x \to 1} h(x) \) is:
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When faced with \( (x^n - 1) / (x - 1) \), the result is always \( n \) as \( x \to 1 \). This follows from the sum of the geometric series \( 1 + x + \dots + x^{n-1} \).
Updated On: May 6, 2026
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The Correct Option is
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