Question:medium

Let $f(x) = |x - 2|$, where $x$ is a real number. Which one of the following is true?

Show Hint

Any function with an absolute value or an even power (like $x^2$) will generally fail to be one-to-one because the negative and positive counterparts often map to the same result.
Updated On: May 6, 2026
  • \( f \text{ is periodic} \)
  • \( f(x+y) = f(x) + f(y) \)
  • \( f \text{ is an odd function} \)
  • \( f \text{ is not a 1-1 function} \)
  • \( f \text{ is an even function} \)
Show Solution

The Correct Option is D

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