Question:medium
Let \( f(x) = |\sin 3x| - |\cos 3x| \), where \( \frac{\pi}{6} \le x \le \frac{\pi}{3} \). Then the value of \( f\left(\frac{\pi}{4}\right) \) is
Let \( f(x) = |\sin 3x| - |\cos 3x| \), where \( \frac{\pi}{6} \le x \le \frac{\pi}{3} \). Then the value of \( f\left(\frac{\pi}{4}\right) \) is
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Check quadrant signs carefully when dealing with modulus of trig functions.
Updated On: Apr 21, 2026
- \( -3\sqrt{2} \)
- \( 3\sqrt{2} \)
- \( -\frac{3}{\sqrt{2}} \)
- \( \frac{3}{\sqrt{2}} \)
- \( 0 \)
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The Correct Option is A
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