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Let \[ f(x)=\frac{|x|-1}{|x-1|} \] be a real valued function from $ \mathbb{R}-\{1\} $ to $B$. If $f$ is a surjection, then $B=$

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To find the codomain of a surjective function, first determine its range. For modulus functions, split the domain at points where the expressions inside the modulus become zero.

Updated On: Jul 29, 2026

$\left[-\dfrac{1}{2},\dfrac{1}{2}\right]$
$[-2,2]$
$[0,1]$
$[-1,1]$

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The Correct Option is D

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Let \[ f(x)=\frac{|x|-1}{|x-1|} \] be a real valued function from \( \mathbb{R}-\{1\} \) to \(B\). If \(f\) is a surjection, then \(B=\)

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The Correct Option is D

Solution and Explanation

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