Question:medium
Let $f(x) = \dfrac{2x+3}{x-2}, \, x \in \mathbb{R}, \, x \neq 2$ and $h(x) = f(f(x))$. Then $h(h(10))$ is equal to:
Let $f(x) = \dfrac{2x+3}{x-2}, \, x \in \mathbb{R}, \, x \neq 2$ and $h(x) = f(f(x))$. Then $h(h(10))$ is equal to:
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If repeated function application gives same value (fixed point), further compositions give the same result.
Updated On: Apr 24, 2026
- $100$
- $20$
- $10$
- $1000$
- $1$
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The Correct Option is C
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