Question:medium
Let $f(x)=\begin{cases}ax+3 & x<1\\ \frac{4x}{a} & x\ge 1\end{cases}$. If $\lim_{x\rightarrow 1}f(x)$ exists, then the possible values of $a$ are
Let $f(x)=\begin{cases}ax+3 & x<1\\ \frac{4x}{a} & x\ge 1\end{cases}$. If $\lim_{x\rightarrow 1}f(x)$ exists, then the possible values of $a$ are
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Logic Tip: When evaluating piecewise functions, the existence of a limit at the boundary always generates an algebraic equation by setting the two "pieces" equal to each other at the boundary value.
Updated On: Apr 27, 2026
- -1, -4
- 1, -4
- 4, -4
- 4, -1
- 1, 4
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The Correct Option is B
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