Let \(f(x)=2\sqrt{\,2\sin x+2\sqrt{2}\cos x\,},\; x\in\mathbb{R}\). Then the value of \(f\!\left(\frac{\pi}{12}\right)\) is equal to
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Converting the form \((\sin x + \cos x)\) to \(\sqrt{2} \sin(x + 45^\circ)\) is often much faster than trying to calculate values for unusual angles like \(15^\circ\) directly.