Question:medium

Let \( f:\mathbb{N}\to\mathbb{N} \) be such that \( f(1)=2 \) and \( f(x+y)=f(x)f(y) \). If \( \sum_{k=1}^{n} f(a+k)=16(2^n-1) \), then \( a \) is

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Functional equations like \( f(x+y)=f(x)f(y) \) usually give exponential functions.
Updated On: May 1, 2026
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Show Solution

The Correct Option is B

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