Question:medium
Let \( \alpha = \sum_{k=0}^{5} {^{10}C_{2k}} \) and \( \beta = \sum_{k=0}^{4} {^{10}C_{2k+1}} \). Then \( \alpha - \beta \) is equal to
Let \( \alpha = \sum_{k=0}^{5} {^{10}C_{2k}} \) and \( \beta = \sum_{k=0}^{4} {^{10}C_{2k+1}} \). Then \( \alpha - \beta \) is equal to
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Sum of even and odd binomial coefficients are equal: each is \(2^{n-1}\).
Updated On: Apr 21, 2026
- \(32 \)
- \(64 \)
- \(128 \)
- \(256 \)
- \(0 \)
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The Correct Option is
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