Let $ABCD$ be a rectangle. If $\overrightarrow{AB} = 5\hat{i} + 4\hat{j} - 3\hat{k}$ and $\overrightarrow{AD} = 3\hat{i} + 2\hat{j} - \hat{k}$, then the length of $BD$ is
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In a rectangle $ABCD$, the diagonal $\overrightarrow{BD} = \overrightarrow{BA} + \overrightarrow{AD}$. Don't confuse $\overrightarrow{BD}$ with $\overrightarrow{BC} + \overrightarrow{CD}$; both routes give the same result by vector addition.