Question:medium

Let \(A = \left[ \begin{array}{ccc}3 & 1 & 2 \\ 1 & 2 & 0 \\ 1 & 1 & 4\end{array} \right]\) and \(pC_{11}+4C_{21}-5C_{32} = -2\), where \(C_{ij}\) denotes the cofactor of an element \(a_{ij}\) of matrix \(A\), then the value of \(p\) is :

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Cofactor C_ij is (-1)^(i+j) times the minor M_ij.
Updated On: Oct 1, 2026
  • \(-2\)
  • \(2\)
  • \(4\)
  • \(3\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Approach
Compute each minor with its sign using the checkerboard pattern $+,-,+$ in the first row.

Step 2: Cofactors
Delete row 1, column 1: minor $2\cdot4-0\cdot1=8$, sign $+$, so $8$.
Delete row 2, column 1: minor $1\cdot4-2\cdot1=2$, sign $-$, so $-2$.
Delete row 3, column 2: minor $3\cdot0-2\cdot1=-2$, sign $-$, so $+2$.

Step 3: Equation
$8p-8-10=-2$ gives $8p=16$, $p=2$. Option (B).

Final Answer:
The cofactors are 8, -2 and 2, which give p = 2, option (B). \[ \boxed{2} \]
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