Question:medium
Let \( A = \begin{bmatrix} 5 & 0 \\ 1 & 0 \end{bmatrix} \) and \( B = \begin{bmatrix} 0 & 1 \\ -1 & 0 \end{bmatrix} \). If \( 4A + 5B - C = 0 \), then the matrix \( C \) is:
Let \( A = \begin{bmatrix} 5 & 0 \\ 1 & 0 \end{bmatrix} \) and \( B = \begin{bmatrix} 0 & 1 \\ -1 & 0 \end{bmatrix} \). If \( 4A + 5B - C = 0 \), then the matrix \( C \) is:
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Always rearrange the matrix equation to isolate the unknown matrix (like \( C \)) on one side before plugging in the numerical values. This prevents sign errors during the arithmetic phase.
Updated On: May 1, 2026
- \( \begin{bmatrix} 5 & 25 \\ -1 & 0 \end{bmatrix} \)
- \( \begin{bmatrix} 20 & 5 \\ -1 & 0 \end{bmatrix} \)
- \( \begin{bmatrix} 5 & -1 \\ 0 & 25 \end{bmatrix} \)
- \( \begin{bmatrix} 5 & 25 \\ -1 & 5 \end{bmatrix} \)
- \( \begin{bmatrix} 0 & 5 \\ 5 & 25 \end{bmatrix} \)
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The Correct Option is B
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