Question:medium
Let A(-4,3), B(0,5) and C(-1,2) be three points. The equation of the straight line which passes through C and bisects the straight-line segment AB is
Let A(-4,3), B(0,5) and C(-1,2) be three points. The equation of the straight line which passes through C and bisects the straight-line segment AB is
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Whenever a line passes through the origin, its constant term \(c\) in \(Ax + By + c = 0\) is zero. Notice that point \((0,0)\) satisfies \(y + 2x = 0\), which is a quick way to verify this type of equation.
Updated On: Jun 24, 2026
- \(y + 2x = 0\)
- \(y - 2x + 2x = 0\)
- \(y + 2x - 4 = 0\)
- \(y + 2x + 4 = 0\)
- \(y - 2x = 0\)
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The Correct Option is A
Solution and Explanation
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