Question:medium

Let A = [1, 2, 3, 4, 5], m be the number of relations such as 4x ≤ 5y XRY and n be the minimum number of elements to be added from A × A to make a symmetric relation. Then the value of n + m.

Updated On: Mar 19, 2026
  • 26
  • 25
  • 24
  • 23
Show Solution

The Correct Option is B

Solution and Explanation

This problem involves understanding relations and their properties. Let's solve the question step-by-step.

Step 1: Understanding R as a Relation

The set \( A = \{1, 2, 3, 4, 5\} \). The relation is defined as \( 4x \leq 5y \), where \( xRy \). This means for each pair \((x, y)\), the condition \( 4x \leq 5y \) must be satisfied.

Step 2: Finding the Number of Relations (m)

We need to find how many pairs \((x, y)\) from \( A \times A \) satisfy \( 4x \leq 5y \).

  • For \( x = 1 \), \( 4 \times 1 = 4 \leq 5y \implies y \geq \frac{4}{5} \). Valid \( y = \{1, 2, 3, 4, 5\} \). Total: 5 pairs.
  • For \( x = 2 \), \( 4 \times 2 = 8 \leq 5y \implies y \geq \frac{8}{5} \). Valid \( y = \{2, 3, 4, 5\} \). Total: 4 pairs.
  • For \( x = 3 \), \( 4 \times 3 = 12 \leq 5y \implies y \geq \frac{12}{5} \). Valid \( y = \{3, 4, 5\} \). Total: 3 pairs.
  • For \( x = 4 \), \( 4 \times 4 = 16 \leq 5y \implies y \geq \frac{16}{5} \). Valid \( y = \{4, 5\} \). Total: 2 pairs.
  • For \( x = 5 \), \( 4 \times 5 = 20 \leq 5y \implies y \geq \frac{20}{5} = 4 \). Valid \( y = \{5\} \). Total: 1 pair.

Adding these, the total number of such pairs is \( m = 5 + 4 + 3 + 2 + 1 = 15 \).

Step 3: Making the Relation Symmetric (n)

A relation is symmetric if whenever \( (x, y) \) is in the relation, \( (y, x) \) is also in the relation.

We have 15 such pairs already. We check which symmetric pairs are missing and need to be added to make the relation symmetric:

  • The pairs naturally symmetric (e.g., (1,1), (2,2), etc.) already satisfy symmetry.

Calculate what remains to make the full relation symmetric by checking \( (y, x) \) for each \((x, y)\). The missing elements to be added will count as \(n\).

Each asymmetric pair will add one missing counterpart:

  • If \((x, y)\) present and not \((y, x)\), count extra.

This needs a systematic calculation or verification. In practice, after symmetry check, found need \(n = 10\) additional pairs added.

Step 4: Solution - Finding \( n + m \)

The total \( n + m \) gives us:

  • As calculated, \( m = 15 \) and \( n = 10 \).

Therefore, \( n + m = 25 \). The correct answer is 25.

Was this answer helpful?
1