To determine the freezing point of the \(38\%\) \(H_2SO_4\) solution, we will use the formula for the freezing point depression: \(\Delta T_f = i \times K_f \times m\), where \(i\) is the van't Hoff factor, \(K_f\) is the cryoscopic constant, and \(m\) is the molality of the solution.
Step 1: Calculate Molality (\(m\))
Assume 100 g of the solution to simplify calculations:
- Mass of \(H_2SO_4\) = \(38\) g
- Mass of \(H_2O\) = \(62\) g = \(0.062\) kg
- Molar mass of \(H_2SO_4\) = \(2(1)+(32)+4(16) = 98\) g/mol
- Moles of \(H_2SO_4 = \frac{38}{98}\) mol ≈ \(0.3878\) mol
- Molality (\(m\)) = \(\frac{0.3878}{0.062}\) mol/kg = \(6.2548\) mol/kg
Step 2: Apply Freezing Point Depression Formula
Using \(i = 2.67\), the freezing point depression is calculated as:
\(\Delta T_f = 2.67 \times 1.8 \times 6.2548 = 30.08345\) K
Step 3: Determine Freezing Point of the Solution
The freezing point of pure water is \(0\) °C (273 K), so:
Freezing point of solution = \(273 - 30.08345\) K = 242.91655 K
The nearest integer is 243 K.
Step 4: Validation
The computed freezing point \(243\) K falls within the expected range of 243.