Question:medium

Krishna walked 20 m towards the north. Then he turned right and walked 30 m. Then he turned right and walked 35 m. Then he turned left and walked 15 m. Finally he turns left and went 15 m. In which direction and how many meters is Krishna compared to from the starting position ?

Show Hint

Use coordinate geometry for direction-distance problems. Assign East as positive x, North as positive y. Calculate net displacement at the end using Pythagoras if needed.
Updated On: Jun 25, 2026
  • 15 m West
  • 30 m East
  • 30 m West
  • 15 m East
  • 45 m East
Show Solution

The Correct Option is

Solution and Explanation


Step 1: Concept Analysis:

Direction and distance problem. Track x (East-West) and y (North-South) coordinates.

Step 2: Solution Approach:

Start at (0,0), facing North.
Step 1: Walk 20m North $\to$ (0, 20).
Step 2: Turn right (now facing East), walk 30m $\to$ (30, 20).
Step 3: Turn right (now facing South), walk 35m $\to$ (30, $-15$).
Step 4: Turn left (now facing East), walk 15m $\to$ (45, $-15$).
Step 5: Turn left (now facing North), walk 15m $\to$ (45, 0).
Final position: (45, 0). East displacement = 45m, North displacement = 0m. Krishna is 45 m East of the start.

Step 3: Conclusion:

Krishna is 45 m East of the starting position.
Was this answer helpful?
0