Question:medium
\(\int \frac{1}{(1 - \cos x)}(1 + \sec x) dx = \)
\(\int \frac{1}{(1 - \cos x)}(1 + \sec x) dx = \)
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The expression \(\frac{\cos x}{\sin^2 x}\) is equivalent to \(\cot x \text{ cosec } x\), whose direct integral is known to be \(-\text{cosec } x\).
Updated On: Jun 25, 2026
- \(\text{cosec } x + C\)
- \(-\text{cosec } x + C\)
- \(\sec x + C\)
- \(-\sec x + C\)
- \(\sec^2 x + C\)
Show Solution
The Correct Option is B
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