Question:medium
\( \int_{0}^{1} \frac{3^{2x}}{3^x + 1}\,dx = \)
\( \int_{0}^{1} \frac{3^{2x}}{3^x + 1}\,dx = \)
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Convert exponential integrals using substitution \( a^x = t \).
Updated On: Apr 21, 2026
- \( \frac{\log_e 5}{2\log_e 3} \)
- \( \frac{\log_e 5}{9\log_e 3} \)
- \( \frac{\log_e 5}{3\log_e 3} \)
- \( \frac{2\log_e 5}{3\log_e 3} \)
- \( \frac{2\log_e 5}{9\log_e 3} \)
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The Correct Option is A
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