Question

In Young's double slit experiment using a source of wavelength \(\lambda\) interference bands are observed on a screen. If the separation between the slits alone is halved in this experiment, then the angular separation \(\omega\) of the fringes on the screen becomes

• A. \(2\omega\)
• B. \(\sqrt{2}\omega\)
• C. \(\frac{\omega}{2}\)
• D. \(\frac{\omega}{\sqrt{2}}\)
• E. \(\frac{\omega}{4}\)

Hint:

\(\omega = \frac{\lambda}{d}\). Smaller slit separation gives wider fringes.

Answer 1

The Correct Option is A