Question:medium
In Young’s double slit experiment, λ = 500nm, d = 1mm, D = 1m. Minimum distance from the central maximum for which intensity is half of the maximum intensity is:
In Young’s double slit experiment, λ = 500nm, d = 1mm, D = 1m. Minimum distance from the central maximum for which intensity is half of the maximum intensity is:
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Half-intensity points in YDSE occur when the phase difference is π/2.
Updated On: Mar 20, 2026
- \( 2.5 \times 10^{-4}\,\text{m} \)
- \( 1.25 \times 10^{-4}\,\text{m} \)
- \( 0.625 \times 10^{-4}\,\text{m} \)
- 0.3125 × 10⁻4m
Show Solution
The Correct Option is D
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