In the reaction of KMnO\(_4\) with an oxalate in acidic medium, MnO\(_4^-\) is reduced to Mn\(^{2+}\) and C\(_2\)O\(_4^{2-}\) is oxidized to CO\(_2\). Hence, 50 mL of 0.02 M KMnO\(_4\) is equivalent to:
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In redox reactions, use stoichiometry to relate the volumes and concentrations of reactants involved.