
To solve the given problem, we will use the Basic Proportionality Theorem (Thales' Theorem), which states that if a line is drawn parallel to one side of a triangle and intersects the other two sides, then it divides those sides proportionally.
Given:
To find: Length of \(BC\)
According to the Basic Proportionality Theorem:
\(\frac{AD}{DB} = \frac{DE}{BC}\)
Substituting the given values:
\(\frac{5}{2.5} = \frac{8}{BC}\)
Solving for \(BC\):
\(\frac{5}{2.5} = 2 \Rightarrow \frac{8}{BC} = 2\)
From the above equation, we have:
\(BC = \frac{8}{2} = 4 \times 3 = 12\, \text{cm}\)
Thus, the length of \(BC\) is 12 cm.

let mid "“ point of sides of $\Delta$ are $(\frac{5}{2}, 3), (\frac{5}{2}, 7) \, \& \, (4, 5)$. If incentre is $(h, k)$ then value of $3h + k$ is:
