In the given circuit, if the potential difference between the points A and B is 90 V and the resistance of the voltmeter is 6000 $\Omega$, then the reading of the voltmeter is
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Whenever a voltmeter has finite resistance, do not treat it as an ideal voltmeter. First combine the voltmeter resistance with the resistor across which it is connected using the parallel combination formula:
\[
R_p=\frac{R_1R_2}{R_1+R_2}
\]
and then apply Ohm's law or voltage division.
