Question

In the following table, match the reactants given in List-I with the correct product in.List-II as per the reaction of hydration of alkene under acidic conditions.

• (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
• (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
• (A) - (II), (B) - (I), (C) - (IV), (D) - (III)
• (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Answer 1

The Correct Option is A

Acid-catalyzed hydration of alkenes adheres to Markovnikov's rule: the hydrogen atom adds to the carbon with fewer hydrogen atoms, and the hydroxyl (OH) group attaches to the carbon with more alkyl substituents (the more substituted carbon). The following table details the reactants and their corresponding products:

List-I (Reactants)	List-II (Products)
(A) Propene	(I) Isopropanol
(B) 2-Methylpropene	(III) 2-Methyl-2-propanol
(C) 1-Butene	(II) 2-Butanol
(D) 2-Butene	(IV) 2-Butanol

Applying Markovnikov's rule and analyzing each reaction confirms the following matches:

• Propene hydration yields Isopropanol, thus (A) corresponds to (I).
• The reaction of 2-Methylpropene produces 2-Methyl-2-propanol, so (B) matches with (III).
• 1-Butene forms 2-Butanol, consistent with Markovnikov's product after potential rearrangement, matching (C) with (II).
• 2-Butene also yields 2-Butanol, indicating that (D) matches with (IV).

Therefore, the correct pairings are (A) - (I), (B) - (III), (C) - (II), and (D) - (IV).