Question

In the following species, how many species have the same magnetic moment? 
(i) Cr\(^{2+}\) 
(ii) Mn\(^{3+}\) 
(iii) Ni\(^{2+}\) 
(iv) Sc\(^{2+}\) 
(v) Zn\(^{2+}\) 
(vi) V\(^{3+}\) 
(vii) Ti\(^{4+}\) 
 

• A. 1
• B. 3
• C. 2
• D. 4

Hint:

Magnetic moment depends on the number of unpaired electrons in the species.

Answer 1

The Correct Option is C

Step 1: {Unpaired Electrons}
Cr\(^{2+}\) and Mn\(^{3+}\) exhibit an equal quantity of unpaired electrons. The number of unpaired electrons, \(n = 4\), yields a magnetic moment of \[ \mu = \sqrt{n(n+2)} = \sqrt{4(4+2)} = \sqrt{24} {BM} \] .