In the following P-V diagram of an ideal gas, two adiabates and two isotherms at T₁=300K and T₂=200K are shown. Values are VA=2, VB=8, VC=16. Find VD.
A particle is moving in a straight line. The variation of position $ x $ as a function of time $ t $ is given as: $ x = t^3 - 6t^2 + 20t + 15 $. The velocity of the body when its acceleration becomes zero is: