Question

In the following figure, the current I is equal to

• A. \(2.9\) A
• B. \(3.9\) A
• C. \(6.2\) A
• D. \(7.5\) A

Hint:

Apply Kirchhoff's current law at each junction in turn.

Answer 1

The Correct Option is D

Step 1: Treat the whole network as one node
All wires are connected, so total current in equals total current out.

Step 2: Sum
Currents in: $4.5+1.7+3.2+4.9=14.3$ A. Currents out other than $I$: $2.3+2.6+1.9=6.8$ A. So $I=14.3-6.8=7.5$ A, option (D).

Final Answer:
$I=7.5$ A, option (D). \[ \boxed{7.5\ \text{A}} \]