The question asks about the product obtained from the reaction:
\(\text{CuO} + \text{H}_2 \rightarrow \text{Cu} + \text{H}_2\text{O}\)
In this reaction, copper(II) oxide \((\text{CuO})\) reacts with hydrogen gas \((\text{H}_2)\) to produce copper \((\text{Cu})\) and water \((\text{H}_2\text{O})\).
Step-by-step Explanation:
- The given reaction is a classic example of reduction, where copper(II) oxide is reduced to copper metal, and hydrogen is oxidized to form water.
- Reduction is a chemical reaction that involves the gain of electrons or a decrease in oxidation state by a molecule, atom, or ion.
- Here, copper is reduced as it goes from the oxidation state of +2 in \(\text{CuO}\) to 0 in metallic copper \((\text{Cu})\).
Conclusion:
The copper obtained from this reaction is referred to as Reduced copper because it has been reduced from its oxidized form (CuO) to its elemental form (Cu).
Hence, the correct answer is Reduced copper.
Elimination of Options:
- Blister copper: It is an impure form of copper that has a blistered appearance due to the release of sulfur dioxide during the smelting process, not relevant to the given reaction.
- Copper scrap: This refers to discarded or leftover copper materials, not related to the chemical reaction described.
- Copper slag: A by-product of the smelting process of copper, it consists of impurities and cannot be the result of the given reaction.