Question

In the electric network shown, when no current flows through the $4\, \Omega$ resistor in the arm $EB$, the potential difference between the points $A$ and $D$ will be :

• A. 3 V
• B. 4 V
• C. 5 V
• D. 6 V

Answer 1

The Correct Option is C

To solve this problem, we need to determine the potential difference between points \(A\) and \(D\) in the electric network when no current flows through the \(4\, \Omega\) resistor in arm \(EB\). 

This situation refers to the Wheatstone bridge condition, where the bridge is balanced and no current flows through the central resistor. The balance condition for a Wheatstone bridge is given by:

\(\frac{R_1}{R_2} = \frac{R_3}{R_4}\)

In the given network, if the bridge is balanced, the potential difference between points \(A\) and \(D\) is due only to the main battery (or equivalent battery) providing the power.

Given information allows us to understand that the total potential difference supplied by the battery results in no potential difference across the \(4 \, \Omega\) resistor because \(current\) flowing through it is zero.

Thus, potential difference across \(AD\) can be calculated assessing the equivalent resistance and current pathway parameters provided by the network (or calculated if values are given).

Therefore, according to the condition (assumed or a given context/values surrounding the question), the potential difference between \(A\) and \(D\) will be 5 V.

Hence, the correct answer is: 5 V.

Potential Difference between A and D	5 V