In the cell reaction
\(\text{Cu(s)} + 2\text{Ag}^+(\text{aq}) \rightarrow \text{Cu}^{2+}(\text{aq}) + 2\text{Ag(s)}\),
\(E^\circ_{\text{cell}} = 0.46\,\text{V}\). By doubling the concentration of \(\text{Cu}^{2+}\), \(E_{\text{cell}}\) is:
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- doubled
- halved
- increases but less than double
- decreases by a small fraction
The Correct Option is D
Solution and Explanation
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