Question:medium

In the alkane \( H_3C-CH_2-C(CH_3)_2-CH_2-CH(CH_3)_2\) , identify 1°,2°,3° carbon atoms and give the number of H atoms bonded to each one of these.

Updated On: Feb 20, 2026
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Solution and Explanation

Given alkane:

H3C − CH2 − C(CH3)2 − CH2 − CH(CH3)2


Concept:

Primary (1°) carbon: Carbon attached to only one other carbon 
Secondary (2°) carbon: Carbon attached to two other carbon atoms 
Terciary (3°) carbon: Carbon attached to three other carbon atoms


Identification of carbon atoms:

1° (Primary) carbon atoms:

All CH3 groups are primary carbons.

Number of 1° carbon atoms = 5

Each 1° carbon is bonded to 3 hydrogen atoms.


2° (Secondary) carbon atoms:

The CH2 groups are secondary carbons.

Number of 2° carbon atoms = 2

Each 2° carbon is bonded to 2 hydrogen atoms.


3° (Tertiary) carbon atoms:

The carbon atoms written as C(CH3)2 and CH(CH3)2 are tertiary carbons.

Number of 3° carbon atoms = 2

Each 3° carbon is bonded to 1 hydrogen atom.


Final Summary: 

Type of carbonNumber of carbonsHydrogen atoms bonded to each
1° (Primary)53
2° (Secondary)22
3° (Tertiary)21
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